#define NMAX 100010
#include <iostream>
#include <stdio.h>
#include <math.h>

using namespace std;

int i,j;
double v[NMAX][2],a,b,sum = 0,mx=0,my=0,suma=0,sumb=0,mins = 2000000000,mina=0, minb=0,nr=0,n,pa=1,pb=1,ps=1;

double calcSum(double c1, double c2) {
	double rez = 0;
	int k;

	for (k=1;k<=n;k++) {
		rez+=(v[k][1] - c1*v[k][0] - c2)*(v[k][1] - c1*v[k][0] - c2);
	}

	return rez;
}

int main() {
	cin>>n;

	for (i=1;i<=n;i++) {
		cin>>v[i][0]>>v[i][1];
	}

	for (i=1;i<=n-1;i++) {
		for (j=i+1;j<=n;j++) {
			if (v[i][0]-v[j][0] != 0) {
			    a = (v[i][1]-v[j][1])/(v[i][0]-v[j][0]);
			    b = v[i][1] - a*v[i][0];

        		sum=calcSum(a,b);
				if (mins > sum) {
					mins = sum;
					mina = a;
					minb = b;
				}

			    suma+=a;
			    sumb+=b;
			    pa*=a;
			    pb*=b;
		  	    nr++;
			} else {
		      // ignore maybe or count as twice not sure
			  // nr++;
			}
		}
	}

	a = suma/nr;
	b = sumb/nr;

	sum=calcSum(a,b);
	if (mins > sum) {
		mins = sum;
		mina = a;
		minb = b;
	}

	a = pow(pa,1/nr);
	b = pow(pb,1/nr);

	sum=calcSum(a,b);
	if (mins > sum) {
		mins = sum;
		mina = a;
		minb = b;
	}

	printf("%f", mins);

	return 0;
}