10 - A+B
A+B is one of the most complex problems on this website due to its large variety of solutions. GolfScript
C
1 #include<stdio.h> 2 3 int main(void) { 4 int a, b; 5 scanf("%d%d", &a, &b); 6 printf("%d", a + b); 7 return 0; 8 }
C++
1 #include<iostream> 2 3 int main(void){ 4 int a, b; 5 std::cin >> a >> b; 6 std::cout << a + b; 7 return 0; 8 }
D
1 import std.stdio; 2 3 void main(){ 4 long a, b; 5 readf("%d %d", &a, &b); 6 writeln(a+b); 7 }
Go
1 package main 2 import "fmt" 3 4 func main() { 5 var a, b int 6 fmt.Scanf("%d%d", &a, &b) 7 fmt.Print(a + b) 8 }
GolfScript
1 ~+
Haskell
1 import Control.Applicative 2 3 main :: IO () 4 main = do 5 [ a, b ] <- map read . words <$> getLine 6 print (a + b :: Int)
Java
In Java, the class must be namedprog
. 1 public class prog { 2 public static void main(final String[] args) { 3 java.util.Scanner scan = new java.util.Scanner(System.in); 4 System.out.println(scan.nextInt() + scan.nextInt()); 5 } 6 }
Oberon
1 MODULE prog; 2 3 IMPORT In, Out; 4 5 VAR a, b : INTEGER; 6 7 BEGIN 8 In.Int(a); 9 In.Int(b); 10 Out.Int(a + b, 0); 11 Out.Ln 12 END prog.
OCaml
1 let sum a b = a + b 2 3 let _= 4 Printf.printf "%i\n" ((Scanf.scanf "%i %i" sum))
Pascal
1 var a,b:integer; 2 begin 3 read(a,b); 4 write(a+b); 5 end.
Perl
1 #!/usr/bin/perl 2 use v5.14; 3 use warnings; 4 5 my ($x, $y) = split ' ', <>; 6 say $x + $y;
PHP
1 <?php 2 fscanf(STDIN, "%d %d\n", $a, $b); 3 echo $a+$b . "\n"; 4 ?>
Python
1 #!/usr/bin/python 2 print sum(map(int, raw_input().split()))
Python3
1 #!/usr/bin/python3 2 print(sum(map(int, input().split())))
Ruby
1 p gets.split(' ').map(&:to_i).inject 0, :+
Rust
1 use std::io; 2 3 fn main() { 4 let mut input = String::new(); 5 6 let _ = io::stdin().read_line(&mut input); 7 8 let mut sum: i64 = 0; 9 for x in input.trim().split(" ").collect::<Vec<&str>>() { 10 sum += match x.parse::<i64>() { 11 Ok(val) => val, 12 _ => 0, 13 }; 14 } 15 16 println!("{}", sum); 17 }
SBCL
1 (format t "~d" (+ (read) (read)))
100 - Transpose
Python 2.7
1 n, m = map(int, raw_input().split()) 2 a = [list(raw_input().split()) for i in range(n)] 3 4 print '\n'.join([' '.join([a[i][j] for i in range(n)]) for j in range(m)])
250 - Spiral
C++ (Inelus Gabriel)
1 #include <cstdio> 2 int N, M, A[1005][1005]; 3 int main() 4 { 5 scanf("%d%d", &N, &M); 6 for(int i = 1; i <= N; ++i) 7 { 8 A[i][0] = A[i][M+1] = -1; 9 for(int j = 1; j <= M; ++j) 10 scanf("%d",&A[i][j]); 11 } 12 13 for(int j = 1; j <= M; ++j) 14 A[0][j] = A[N+1][j] = -1; 15 16 int i = 1, j = 1, ok = 1; 17 printf("%d ",A[i][j]); A[i][j] = -1; 18 while(ok) { 19 ok = 0; 20 while(A[i][j+1] != -1) { ok = 1; ++j; printf("%d ", A[i][j]); A[i][j] = -1; } 21 while(A[i+1][j] != -1) { ok = 1; ++i; printf("%d ", A[i][j]); A[i][j] = -1; } 22 while(A[i][j-1] != -1) { ok = 1; --j; printf("%d ", A[i][j]); A[i][j] = -1; } 23 while(A[i-1][j] != -1) { ok = 1; --i; printf("%d ", A[i][j]); A[i][j] = -1; } 24 } 25 return 0; 26 }
Python 2.7 (Sergiu Puscas)
1 n, m = map(int, raw_input().split()) 2 a = [list(raw_input().split()) for i in range(n)] 3 4 U, D, L, R = 0, n-1, 0, m-1 5 direction = 0 6 i, j = 0, 0 7 8 for step in range(n*m): 9 print a[i][j], 10 11 if direction == 0: # right 12 if j+1 > R: # change to down 13 direction = 1 14 R -= 1 15 i += 1 16 else: 17 j += 1 18 19 elif direction == 1: # down 20 if i+1 > D: # change to left 21 direction = 2 22 D -= 1 23 j -= 1 24 else: 25 i += 1 26 27 elif direction == 2: # left 28 if j - 1 < L: # change to up 29 direction = 3 30 L += 1 31 i -= 1 32 else: 33 j -= 1 34 35 elif direction == 3: # up 36 if i - 1 <= U: # change to right 37 direction = 0 38 U += 1 39 j += 1 40 else: 41 i -= 1